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So we actually have 18 possible outcomes when two colors are choosen. The possible outcomes for 3 different colors is the permutation of selecting 3 different marbles: C(3 colors)= 3P3= 6 so there are a total of 30 choices.

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Answers ( 2) A bag contains 3 red marbles and 4 blue marbles. a marble is taken at random and replaced. Another marble is taken from the bag. Work out the probability that the two marbles taken from the bag are the same color. Total number of marbles in the bag is 3 + 4 = 7.

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8 Likes, 0 Comments - Thom Gibson (@gibsoneducation) on Instagram: “A bag contains colored marbles. The ratio of red marbles to blue marbles is 1:4. The ratio of blue…”

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A Box Contains Five Blue Eight Green And Three Yellow Marbles If A Marble Is Selected At Random, What Is The Probability That It Is Yellow? Algebra. 3/(5+8+3) = 3/16The probability of drawing one of 3 yellow marbles from a box of 16 marbles is 3/16.... In A Bag There Are 2 Red, 3 Yellow, 4 Green, And 6 Blue Marbles. What Is The Probability Of ...

A bag contains 3 red marbles, 2 blue marbles and 5 yellow marbles. One marble is drawn at random. What is the probability of getting a red marble? Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both A bag contains 2 red, 3 green and 2 blue balls.

Marlon begins removing marbles from the bag at random, one at a time. You need to identify the marble with smallest number which is the red that has only 3. Then add all the remaining marble which is the white and blue.Oct 04, 2020 · 12 marbles: Red: 5 Green: 3 Blue: 4 A: The probability of consecutively choosing two red marbles and a green marble without replacement. The probability of choosing first red marble is 5/12, because there is not any replacement now 4 red marbles are remained and totally 11 marbles. Thus the probability of choosing the second red marble is 4/11. May 30, 2013 · A bag contains 6 red marbles, 4 blue marbles, 7 green marbles, and 3 yellow marbles. A marble is drawn from the bag and is not replaced. Then a second marble is drawn. Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both A bag contains 2 red, 3 green and 2 blue balls.

A box contains 10 red marbles, 20 blue marbles nad 30 green marbles. Tara has two bags of marbles the first bag contains 6 red marbles 5 blue marbles and 4 Green marble...

There are four boxes, A, B C and D containing marbles. A contains 1 red, 6 white and 3 black marbles, B contains 6 red, 2 white and 2 black marbles, C contains 8 red, 1 white an 1 black marles, and D contains 6 white and 4 black marbles. One of the boxes is selected at random and a single marble is drawn from it. Total number of marbles in the bag is 3 + 4 = 7. The problem asks for the probability of (RR) or (BB) . It's worthy to note we are replacing the balls Not Sure About the Answer? 💡 Find an answer to your question "A bag contains 3 red marbles and 4 blue marbles.A bag contains 2 green, 3 red and 4 black balls. A ball is taken out of the bag at random. Find the probability that the selected ball is (i) not green (ii) not black.

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